## Kata

https://www.codewars.com/kata/sum-of-intervals/python

Write a function called sumIntervals/sum_intervals() that accepts an array of intervals, and returns the sum of all the interval lengths. Overlapping intervals should only be counted once.

### Intervals

Intervals are represented by a pair of integers in the form of an array. The first value of the interval will always be less than the second value. Interval example: [1, 5] is an interval from 1 to 5. The length of this interval is 4.

### Overlapping Intervals

List containing overlapping intervals:

[ [1,4], [7, 10], [3, 5] ]

The sum of the lengths of these intervals is 7. Since [1, 4] and [3, 5] overlap, we can treat the interval as [1, 5], which has a length of 4.

### Examples:

sumIntervals( [ [1,2], [6, 10], [11, 15] ] ); // => 9 sumIntervals( [ [1,4], [7, 10], [3, 5] ] ); // => 7 sumIntervals( [ [1,5], [10, 20], [1, 6], [16, 19], [5, 11] ] ); // => 19

## My Solution

def sum_of_intervals(intervals): numbers = [] for interval in intervals: for i in range(interval[0],interval[1]): numbers.append(i) return len(set(numbers))